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CH3CH2CHO +2 Cu(OH)2 -(temperatura)->CH3CH2COOH + Cu2O +2 H20
CH3CH2COOH + KOH --> CH3CH2COOK + H2O
b) C6H5CH3OH + CuO --> C6H5CHO + Cu + H2O
C6H5CHO + 2 Cu(OH)2 -(T)-> C6H5COOH + Cu2O + 2 H2O
C6H5COOH + KOH --> C6H5COOK + H2O
b) 460 g toluenu ---- 948 g KMnO4
86g toluenu ---- x KMnO4
x=177,2 g
177,2 g ---- 40%
y----- 100%
y=443g
Odp. 443 g 40-procentowego roztworu KMnO4