Question

Rozwiąż układy równań
a) 10x+8y+11=0
2x+√2y=-3

b) 2x-4y=√3
x+y=√2

C)2x-y√2=6+√2
x√2+2y=3√2-2

Answer 1

Rozwiąż układy równań
a) 10x+8y+11=0
2x+√2y=-3

10x = -8y -11
2x+√2y=-3

10x = -8y -11/:10
2x+√2y=-3

x = -8/10 y - 11/10
2(-8/10 y - 11/10) +√2y=-3

x = -8/10 y - 11/10
-1,6y - 4,4 +√2y=-3

x = -8/10 y - 11/10
-1,6y + √2y = 4,4 -3

x = -8/10 y - 11/10
(√2-1,6)y = 1,4

x = -8/10 y - 11/10
(√2-1,6)y = 1,4/ : (√2-1,6)

x = -8/10 y - 11/10
y = 1,4/(√2-1,6)

x = -8/10 * [1,4/(√2-1,6)] - 11/10
y = 1,4/(√2-1,6)

x = -123√2 + 355,2/ 10(√2-1,6)
y = 1,4/(√2-1,6)

x = 12,3√2 - 22,2
y = 1,4/(√2-1,6)


b) 2x-4y=√3
x+y=√2

2x-4y=√3
x =√2 -y

2(√2 -y) - 4y=√3
x =√2 -y

2√2 -2 y - 4y=√3
x =√2 -y

-6y = √3 - 2√2 /: (-6)
x =√2 -y

y = - √3/6 + 2√2 /6
x =√2 -y

y = - √3/6 + 2√2 /6 /* 6
x =√2 -y

y = - √3 + 2√2
x =√2 -y

y = - √3 + 2√2
x =√2 - (- √3 + 2√2 )

y = - √3 + 2√2
x = √3 - √2


C)2x - y√2 =6+√2
x√2 + 2y = 3√2-2

2x = y√2 + 6 + √2
x√2 + 2y = 3√2-2

2x = y√2 + 6 + √2 /:2
x√2 + 2y = 3√2-2

x = y√2/2 + 3 + √2/2
x√2 + 2y = 3√2-2