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2x-3y=2
y=3-3x
2x-3(3-3x)=2
y=3-3x
2x-9+9x=2
y=3-3x
11x=11
y=3-3x
x=1
y=3-3
x=1
y=0
x=1
2x-3y=2
z pierwszego: y = 3-3x
podstawiam do drugiego:
2x - 3(3-3x) = 2
11x = 11
x = 1
podstawiam do mojego wzoru na y:
y = 3-3*1 = 0
2x-3y=2
y=3-3x
2x-3(3-3x)=2
y=3-3x
2x-9+9x=2
y=3-3x
11x=2+9
y=3-3x
11x=11
x=1
y=3-3×1=0