September 2018 1 34 Report

Rozwiąż równanie:

7^{x+1} = 3^{2x-2}

Wg przykładu:

 7^{x} = 4^{2} * 4^{x} \\7^{x} = 16*4^{x}\\ \frac{7^x}{4^x}=16\\(\frac{7}{4})^{x}=16\\ x=log_{\frac{7}{4}}16

Z góry serdecznie dziekuje


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