Rozwiąż równanie:
(8/5)^(2x+1/x-1) = (5/8)^3(3-x)
(8/5)^(2x+1/x-1) = (8/5)^-3(3-x)
opuszczam podstawy:
2x+1
------ = -3(3-x) /*(x-1)
x-1
zał. x≠1
2x+1 =-3(3-x)(x-1)
2x+1=-3(3x-3-x²+x)
2x+1 = -3(-x²+4x-3)
2x+1 = 3x²-12x+9
3x²-14x+8=0
Δ=b²-4ac=196 - 96 = 100 √Δ=10
x1=(14-10)/6=4/6=2/3
x2=(14+10)/6=24/6=4
odp.
x=2/3 ∨ x=4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
(8/5)^(2x+1/x-1) = (5/8)^3(3-x)
(8/5)^(2x+1/x-1) = (8/5)^-3(3-x)
opuszczam podstawy:
2x+1
------ = -3(3-x) /*(x-1)
x-1
zał. x≠1
2x+1 =-3(3-x)(x-1)
2x+1=-3(3x-3-x²+x)
2x+1 = -3(-x²+4x-3)
2x+1 = 3x²-12x+9
3x²-14x+8=0
Δ=b²-4ac=196 - 96 = 100 √Δ=10
x1=(14-10)/6=4/6=2/3
x2=(14+10)/6=24/6=4
odp.
x=2/3 ∨ x=4