Rozwiąż równanie:
x² - x = 10
x² - x - 10 = 0
a = 1, b = -1, c = -10
Δ = b^2 - 4ac = 1 - 4*1*(-10) = 1+40 = 41
√Δ = √41
x1 = (-b-√Δ)/2a = (1-V41)/2
x2 = (-b+√Δ)/2a = (1+V41)/2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x² - x = 10
x² - x - 10 = 0
a = 1, b = -1, c = -10
Δ = b^2 - 4ac = 1 - 4*1*(-10) = 1+40 = 41
√Δ = √41
x1 = (-b-√Δ)/2a = (1-V41)/2
x2 = (-b+√Δ)/2a = (1+V41)/2