Rozwiąż równanie:
1. ( x-3)(x+2)=(x+4)(2-x)-14
x²+2x-3x-6=2x-x²+8-4x-14
x²-1x-6=-x²-2x-6
2x²+x=0
Δ=1²
√Δ=1
x₁=-1-1/2*2 =-½x₂=-1+1/2*2-0
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x²+2x-3x-6=2x-x²+8-4x-14
x²-1x-6=-x²-2x-6
2x²+x=0
Δ=1²
√Δ=1
x₁=-1-1/2*2 =-½
x₂=-1+1/2*2-0