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x(x+1)²=x(x+1)(x+1)(x²-x+1) ze wzoru: a³+b³=(a+b)(a²-ab+b²)
x(x+1)²- x(x+1)²(x²-x+1) =0
x(x+1)² (1-(x²-x+1)=0
x(x+1)² (1-x²+x-1)=0
x(x+1)² (-x²+x)=0
x(x+1)² (-x)(x-1)=0
-x²(x+1)²(x-1)=0
x=0 x=-1 x=1
0 i -1 - podwójne pierwiastki