Rozwiąż równanie: x3 + 4x2 + 3 = x(x – 2)2 + 7x
x³+4x²+3 =x(x-2)²+7x
x³+4x²+3 = x(x²-4x+4)+7x
x³+4x²+3 = x³-4x²+4x+7x
x³-x³+4x²+4x²-4x-7x+3=0
8x²-11x +3 =0
Δ=121-96=25
√Δ=5
x1=11-5/16=6/16=3/8
x2=11+5/16=16/16=1
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x³+4x²+3 =x(x-2)²+7x
x³+4x²+3 = x(x²-4x+4)+7x
x³+4x²+3 = x³-4x²+4x+7x
x³-x³+4x²+4x²-4x-7x+3=0
8x²-11x +3 =0
Δ=121-96=25
√Δ=5
x1=11-5/16=6/16=3/8
x2=11+5/16=16/16=1