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-x³ -3x²+4x = 0
-x(x² + 3x - 4) = 0
-x = 0 lub (x² + 3x - 4) = 0
x = 0 ∆ = b² - 4ac = 3² - 4*1*(-4) = 9 + 16 = 25
√∆ = √ 25 = 5
x1= (-b - √∆):2a = (-3 - 5) : 2*1 = (-8 ): 2 = - 4
x2= (-b + √∆):2a = (-3 + 5) : 2*1 = 2 : 2 = 1
Odp. rozwiazaniem równania jest
x = 0 lub x = - 4 lub x = 1