2x²+15x-27
------------ = 0
9x²+4
D.:
9x²+4≠0
x∈R ponieważ 9x²+4>0
2x²+15x-27=0
Δ=15²-4*2*(-27)=441
√Δ=21
x1=(-15-21)/4=-9
x2=(-15+21)/4=1,5
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2x²+15x-27
------------ = 0
9x²+4
D.:
9x²+4≠0
x∈R ponieważ 9x²+4>0
2x²+15x-27=0
Δ=15²-4*2*(-27)=441
√Δ=21
x1=(-15-21)/4=-9
x2=(-15+21)/4=1,5