Question

Rozwiąż równanie.
a. x(x^2 - 16) = 0
b. x(x^2 + 16) = 0
c. x(4x^2 + 1) = 0
d. x(x^2 + 2x + 1) = 0
e. x(x^2 - 4x + 4) = 0
f. x(4x^2 - 4x + 1) = 0

Answer 1

A)
x(x^2 - 16)=0 | :x
x^2 - 16 = 0   | +16
x^2=16
x=4
b)
x(x^2 + 16)=0
x^2+16=0
x^2=-16
x= 
c)
x(4x^2 + 1)=0
4x^2+1=0
4x^2=-1 |:4
x^2= -
x= 
d)
x(x^2+2x+1)=0
x^2+2x+1=0
(x+1)^2=0   według zasady (a+b)^2=a^2+ 2ab + b^2
x+1=0
x= -1
e)
x(x^2-4x+4)=0
x^2=4x+4=0
(x-2)^2=0
x-2=0
x=2
f)
x(4x^2 + 2x + 1)=0
4x^2 + 2x +1 =0
(2x+ 1)^2=0
2x+1=0
x=
licze na naj :D