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x³(x²-8)+(x²-8)=0
(x²-8)(x³+1)=0
(x+2√2)(x-2√2)(x³+1)=0
Odp. x∈{-2√2, -1, 2√2}
b)
x³(2x+1)-1/8(2x+1)=0
(2x+1)(x³-1/8)=0'
2x=-1 v x³=1/8
Odp. x∈{-1/2, 1/2}