Rozwiąż nierównośc:
x(x-3)< 2x^2
x²-3x-2x²<0
-x²-3x<0
-x(x+3)<0
x=0 v x=-3
x∈(-∞,-3) v (0,∞)
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x(x-3)< 2x^2
x²-3x-2x²<0
-x²-3x<0
-x(x+3)<0
x=0 v x=-3
x∈(-∞,-3) v (0,∞)