Rozwiąż nierówności kwadratową : (2x-3)²<1
(2x-3)² < 1
(a-b)² = a²-2ab+b²
4x²-12x+9 < 1
4x²-12+9-1 < 0
4x²-12x+8 < 0 /:4
x²-3x+2 < 0
a = 1, b = -3, c = 2
Δ = b²-4ac = 9-4·1·2 = 9-8 = 1
√Δ = √1 = 1
x₁ = (-b-√Δ)/2a = (3-1)/2 = 1
x₂ = (-b+√Δ)/2a = (3+1)/2 = 2
a = 1 > 0 ramiona paraboli skierowane w górę
x ∈ (1; 2)
_______________
_______________________;)
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(2x-3)² < 1
(a-b)² = a²-2ab+b²
4x²-12x+9 < 1
4x²-12+9-1 < 0
4x²-12x+8 < 0 /:4
x²-3x+2 < 0
a = 1, b = -3, c = 2
Δ = b²-4ac = 9-4·1·2 = 9-8 = 1
√Δ = √1 = 1
x₁ = (-b-√Δ)/2a = (3-1)/2 = 1
x₂ = (-b+√Δ)/2a = (3+1)/2 = 2
a = 1 > 0 ramiona paraboli skierowane w górę
x ∈ (1; 2)
_______________
_______________________;)