Question

Rozwiąż nierówność:

c) |3y + 5| 4

d) |x+3| >3

e) |4z +1 | >5

f) |3-5x|-2 > 0

Answer 1

c) 3y </  -5+4 = 3y </ - 1 = y </ -1/3

d) x + 3 > 3 = x > 3-3 = x > 0

e) 4z + 1 > 5 = 4 z > 5-1 = 4z > 4 = z >1

f) 3-5z - 2 > 0 = -5z > -3+2 = -5z > -1 | :(-1) = z < 1

Answer 2

|3y + 5|  4

3y + 5  4    3y + 5 ≥- 4

y≤-⅓ v y≥-3

 

d) x+3 >3   x+3 <-3

x>0 v x<-6

 

e) 4z +1  >5   4z +1  <-5

z>1 v z<-1½

f) 3-5x > 2  3-5x<-2

-5x>-1   -5x<-5

x<⅕   v x>1