Question

Rozwiąż układ równan:

6x-2y=10

3x+4(1-y)=36

2y=1/3(x-1)+7

1-x+4(y-1)

Answer 1

6x - 2y = 10         /razy -2
3x - 4y = 32

 

-12x + 4y = -20

3x - 4y = 32

 

-9x = 12

 

x= 1 i 1/3

-2y = 10 - 6x

 

x= 1 i 1/3

y = 3

 

 

tu masz chyba zle wpisane

Answer 2

6x-2y=10

3x+4(1-y)=36

 

6x-2y=10/:(-2)

3x+4-4y=36

 

y=-5+3x

3x-4(-5+3x)=32

3x+20-12x=32

-9x=12

x=-1⅓

 

y=-5+3*(-1⅓)

y=-5-4

y=-9

 

 

 

2y=1/3(x-1)+7

1-x=4(y-1)

 

2y=⅓x-⅓+7

1-x=4y-4

 

-⅓x+2y=7⅓

-x-4y=-5/:(-1)

 

x=5-4y

-⅓(5-4y)+2y=7⅓

-1⅔+1⅓y+2y=7⅓

2⅓y=9

y=3⁶/₇

 

x=5-4*3⁶/₇

x=5-15³/₇

x=-10³/₇