Rozwiąż nierówność m-8x≥0, jezeli m=log√3 9.
m = log√3 9√3 do potęgi m = 93 do potęgi 1/2m = 3²1/2 m = 2m = 4m - 8x ≥ 04 - 8x ≥ 0- 8x ≥ -4 /:(-8)x ≤ 0,5
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m = log√3 9
√3 do potęgi m = 9
3 do potęgi 1/2m = 3²
1/2 m = 2
m = 4
m - 8x ≥ 0
4 - 8x ≥ 0
- 8x ≥ -4 /:(-8)
x ≤ 0,5