potrzebuje zadanie 4,6 i 8 ;) zadania w zalaczniku
zad 4 C5H10 + 5O2 = 5CO + 5H2OC9H20 + 5O2= 9C +10H2OC3H8 + 5O2 = 3CO2 + 4H2O
zad 6 CH3 (KRESKA W DÓŁ XD) CH2 = CH - CH - CH2 - CH2 - CH3A) CH3 (KRESKA W DÓŁ)
CH2 = C - CH2 - CH2 - CH2 - CH3
B) 2 - metykolheks - 1-en
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zad 4
C5H10 + 5O2 = 5CO + 5H2O
C9H20 + 5O2= 9C +10H2O
C3H8 + 5O2 = 3CO2 + 4H2O
zad 6
CH3 (KRESKA W DÓŁ XD)
CH2 = CH - CH - CH2 - CH2 - CH3
A) CH3 (KRESKA W DÓŁ)
CH2 = C - CH2 - CH2 - CH2 - CH3
B) 2 - metykolheks - 1-en