x³-5x²+6x=x(x²-5x+6)=x(x-2)(x-3)
Δ=b²-4ac=25-24=1
x₁=[-b-√Δ]/2a=[5-1]/2=2
x₂=[-b+√Δ]/2a=[5+1]/2=3
x³-5x²+6x=x(x²-5x+6)
Δ=25-24=1
√Δ=1
x 1=(5-1)/2=2
x 2=(5+1)/2=3
x³-5x²+6x=x(x-2)(x-3) po rozlozeniu na czynniki
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x³-5x²+6x=x(x²-5x+6)=x(x-2)(x-3)
Δ=b²-4ac=25-24=1
x₁=[-b-√Δ]/2a=[5-1]/2=2
x₂=[-b+√Δ]/2a=[5+1]/2=3
x³-5x²+6x=x(x²-5x+6)
Δ=25-24=1
√Δ=1
x 1=(5-1)/2=2
x 2=(5+1)/2=3
x³-5x²+6x=x(x-2)(x-3) po rozlozeniu na czynniki
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