średnica podstawy walca o objetości 0,36pi dm sześciennych ma 12cm.Jaką wysokosc ma ten walec pomurzcie
1dm = 10 cm
V = 0,36pi dm^3 V=Pp*h h=V/Pp
r = 0,6dm
pole podstawy =pir^2 to P=0,36pi dm^2
h = 0,36pi / 0,36pi
h = 1 dm = 10 cm
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1dm = 10 cm
V = 0,36pi dm^3 V=Pp*h h=V/Pp
r = 0,6dm
pole podstawy =pir^2 to P=0,36pi dm^2
h = 0,36pi / 0,36pi
h = 1 dm = 10 cm