Question

Quiz Math LIMIT

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Answer 1

Verified answer

Kelas 11 Matematika
Bab Limit

lim (3x - sin 2x)/(4x - tan 3x)
x→0

= (3 . 0 - sin 2 . 0)/(4 . 0 - tan 3 . 0)
= (0 - 0)/(0 - 0)
= 0/0 (L 'Hospital)

lim (3x - sin 2x)/(4x - tan 3x)
x→0

= lim (3 - 2 . cos 2x)/(4 - 3 sec² 3x)
...x→0

= (3 - 2 . cos 0)/(4 - 3 . sec² . 0)
= (3 - 2 . 1)/(4 - 3 . 1)
= 1/1
= 1

Answer 2

Lim (3x-sin2x) / (4x-tan3x)
X 》0

(3 x 0 - sin 2 × 0) / (4 x 0 - tan 3 × 0)
(0 - 0) / (0 - 0)

lim (3x - sin 2x) / (4x - tan3x)
X 》 0

jadi
lim (3 - 2 × cos2x) / (4 - 3sec^2 3x)

x yaitu x 》 0

= (3 - 2 × cos 0) / (4 - 3 × sec^2 × 0)
= (3 - 2 × 1) / (4 - 3 × 1)
= 1 / 1
= 1