25.Dari persamaan parabola tersebut, diketahui pers.sb.simetri x = -b/2a.
absis titik Q :
-b/2a + -b/2a - x0
= -2 b/2a - x0
= - b/a - x0 <= dikarenakan simetri
26.x = k <= sb.simetri dari parabola
f(x) = 2x² - 6x - 5
a = 2
b = (-6)
c = -5
x = -b/2a
x = -(-6)/2(2)
x = 6/4
x = 3/2
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Mapel : Matematika
Materi : Fungsi Komposisi
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25.Dari persamaan parabola tersebut, diketahui pers.sb.simetri x = -b/2a.
absis titik Q :
-b/2a + -b/2a - x0
= -2 b/2a - x0
= - b/a - x0 <= dikarenakan simetri
26.x = k <= sb.simetri dari parabola
f(x) = 2x² - 6x - 5
a = 2
b = (-6)
c = -5
x = -b/2a
x = -(-6)/2(2)
x = 6/4
x = 3/2
________________________________
Mapel : Matematika
Materi : Fungsi Komposisi