Przedstaw w postaci iloczynu:
- (x+y)*a+(x+y)*b
- 3(z-y)-a(z-y)
- (m-1)(k-1) + (k-1)(m+1)
- (a-1(b+c)-(a-1)(b-c)
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a) (x + y) a + (x + y) b =
ax+ay+bx+by
B) 3(z-y) - a(z-y) =
3z-3y-az+y
C) (m-1)(k-1)+(k-1)(m+1) =
(mk-1m-1k+1)+(mk+1k-1m-1)=
2mk-2m
D) (a-1)(b+c)-(a-1)(b-c) =
ab+a-1b-1c-(ab-ac-1b+1c)=
ab+a-1b-1c-ab+ac+1b-1c=
a-2c+ac