prosze pilnie o zad 13,16 z zalacznika! dam NAJ!
Zadanie 13a) Nie da się wyniku zapisać w postaci jednej potęgi o podstawie 4b) Zadanie 16
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Zadanie 13
![4^8:8^3\cdot 16^2:2\cdot 32=(2^2)^8:(2^3)^3\cdot (2^4)^2:2 \cdot 2^5=2^{16}:2^9\cdot 2^8:2\cdot 2^5= 4^8:8^3\cdot 16^2:2\cdot 32=(2^2)^8:(2^3)^3\cdot (2^4)^2:2 \cdot 2^5=2^{16}:2^9\cdot 2^8:2\cdot 2^5=](https://tex.z-dn.net/?f=4%5E8%3A8%5E3%5Ccdot+16%5E2%3A2%5Ccdot+32%3D%282%5E2%29%5E8%3A%282%5E3%29%5E3%5Ccdot+%282%5E4%29%5E2%3A2+%5Ccdot+2%5E5%3D2%5E%7B16%7D%3A2%5E9%5Ccdot+2%5E8%3A2%5Ccdot+2%5E5%3D)
![2^7\cdot 2^8:2\cdot 2^5=2^7\cdot 2^8:2\cdot 2^5=2^{15}:2\cdot 2^5=2^{14} \cdot 2^5=2^{19} 2^7\cdot 2^8:2\cdot 2^5=2^7\cdot 2^8:2\cdot 2^5=2^{15}:2\cdot 2^5=2^{14} \cdot 2^5=2^{19}](https://tex.z-dn.net/?f=2%5E7%5Ccdot+2%5E8%3A2%5Ccdot+2%5E5%3D2%5E7%5Ccdot+2%5E8%3A2%5Ccdot+2%5E5%3D2%5E%7B15%7D%3A2%5Ccdot+2%5E5%3D2%5E%7B14%7D+%5Ccdot+2%5E5%3D2%5E%7B19%7D)
![9^4 \cdot 27^3 \cdot 81 \cdot 3^7=9^4\cdot (3^3)^3 \cdot 9^2 \cdot 3^7=9^6\cdot 3^9 \cdot 3^7=9^4 \cdot 3^16=9^6\cdot (3^2)^8=9^6\cdot 9^8=9^{14} 9^4 \cdot 27^3 \cdot 81 \cdot 3^7=9^4\cdot (3^3)^3 \cdot 9^2 \cdot 3^7=9^6\cdot 3^9 \cdot 3^7=9^4 \cdot 3^16=9^6\cdot (3^2)^8=9^6\cdot 9^8=9^{14}](https://tex.z-dn.net/?f=9%5E4+%5Ccdot+27%5E3+%5Ccdot+81+%5Ccdot+3%5E7%3D9%5E4%5Ccdot+%283%5E3%29%5E3+%5Ccdot+9%5E2+%5Ccdot+3%5E7%3D9%5E6%5Ccdot+3%5E9+%5Ccdot+3%5E7%3D9%5E4+%5Ccdot+3%5E16%3D9%5E6%5Ccdot+%283%5E2%29%5E8%3D9%5E6%5Ccdot+9%5E8%3D9%5E%7B14%7D)
![2^{2x}\cdot32^{3x+4}=128 2^{2x}\cdot32^{3x+4}=128](https://tex.z-dn.net/?f=2%5E%7B2x%7D%5Ccdot32%5E%7B3x%2B4%7D%3D128)
![2^{2x}\cdot2^{5(3x+4)}=2^7 2^{2x}\cdot2^{5(3x+4)}=2^7](https://tex.z-dn.net/?f=2%5E%7B2x%7D%5Ccdot2%5E%7B5%283x%2B4%29%7D%3D2%5E7)
![2^{2x+5(3x+4)}=2^7 2^{2x+5(3x+4)}=2^7](https://tex.z-dn.net/?f=2%5E%7B2x%2B5%283x%2B4%29%7D%3D2%5E7)
![2x+5(3x+4)=7 2x+5(3x+4)=7](https://tex.z-dn.net/?f=2x%2B5%283x%2B4%29%3D7)
![2x+15x+20=7 2x+15x+20=7](https://tex.z-dn.net/?f=2x%2B15x%2B20%3D7)
![2x+15x=7-20 2x+15x=7-20](https://tex.z-dn.net/?f=2x%2B15x%3D7-20)
![17x=-13 17x=-13](https://tex.z-dn.net/?f=17x%3D-13)
![x=- \frac{13}{17} x=- \frac{13}{17}](https://tex.z-dn.net/?f=x%3D-+%5Cfrac%7B13%7D%7B17%7D)
a)
Nie da się wyniku zapisać w postaci jednej potęgi o podstawie 4
b)
Zadanie 16