prosze o rozwiązanie :) : *
a)-3*(3(-3)^2 -1)=-3*(-26)= 78
b)3*(-1)^3 +2((-1)^2 +1)= -4+4=1
c)3*((-1)^2 -1) -3((-1)+1)=0
d)3(-3)*(-3+(-2)-(-2)^2*(-2)=-9*(-5)-4=45-4=41
e) 1/5 *10 *(1/2 8(10) - 5/6 *(12)) - 1/3 8 12 = 2*(5-10) -4 = -10 -4= -14
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a)-3*(3(-3)^2 -1)=-3*(-26)= 78
b)3*(-1)^3 +2((-1)^2 +1)= -4+4=1
c)3*((-1)^2 -1) -3((-1)+1)=0
d)3(-3)*(-3+(-2)-(-2)^2*(-2)=-9*(-5)-4=45-4=41
e) 1/5 *10 *(1/2 8(10) - 5/6 *(12)) - 1/3 8 12 = 2*(5-10) -4 = -10 -4= -14