Ile gramów tlenu potrzeba do spalenia 40g potasu. prosze daje naaaj! ;)
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2K + O2 ---> 2K2O
m2K= 39g *2= 78g
mO2= 32g
78g K --- 32g O2
40g K --- xg O2
x= 16,41g ---> tyle gram tlenu potrzeba do spalenia 40g potasu
Pozdrawiam, kate66 ;)