Question

prosze o pomoc i szybkie rozwiązanie

z góry dzięuje

Answer 1

 

z.2

a) an = 3n -2

a1 = 3*1 - 2 = 3 -2 = 1

a2 = 3*2 - 2 = 6 -2 = 4

a3 = 3*3 - 2 = 9 - 2 = 7

a4 = 3*4 - 2 = 12 -2 = 10

a5 = 3*5 - 2 = 15 - 2 = 13

b)

bn = (3/2)* 2^n

b1 = (3/2)* 2^1 = (3/2) *2 = 3

b2 = (3/2)*2^2 =  (3/2)*4 =  6

b3 = (3/2)*2^3 =  (3/2)*8 = 12

b4 = (3/2)*2^4 =  (3/2)*16 = 24

b5 = (3/2)*2^5 =  (3/2)*32 = 48

==========================

 

cdn. później