proporcje
b-2/b+1=b/1-3
pilnie potzeróbje
(b-2)(1-3)=b(b+1)
-2(b-2)=b²+b
-2b+4=b²+b
b²+3b-4=0
Δ=b²-4ac
Δ=9+16=25
√Δ=5
x₁=(-b-√Δ)/2a
x₁=(-3-5)/2=-8/2=(-4)
x₂=(-b+√Δ)/2a
x₂=(-3+5)/2=2/2=1
x∈{-4,1}
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(b-2)(1-3)=b(b+1)
-2(b-2)=b²+b
-2b+4=b²+b
b²+3b-4=0
Δ=b²-4ac
Δ=9+16=25
√Δ=5
x₁=(-b-√Δ)/2a
x₁=(-3-5)/2=-8/2=(-4)
x₂=(-b+√Δ)/2a
x₂=(-3+5)/2=2/2=1
x∈{-4,1}