prosze o pomoc funkcja kwadratowa f[x] = -2xdo kwadr.-4x+6 sprowadz do postaci iloczynowej pomoze mi ktos?
-2x²-4x+6
Δ=(-4)²-4*(-2)*6
Δ=16+48
Δ=64
√Δ=8
x₁=4-8/-4=-4/-4=1
x₂=4+8/-4=12/-4=-3
postać iloczynowa: y=a(x-x₁)(x-x₂)
a=-2
y=-2(x-1)(x-(-3)
y=-2(x-1)(x+3)
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-2x²-4x+6
Δ=(-4)²-4*(-2)*6
Δ=16+48
Δ=64
√Δ=8
x₁=4-8/-4=-4/-4=1
x₂=4+8/-4=12/-4=-3
postać iloczynowa: y=a(x-x₁)(x-x₂)
a=-2
y=-2(x-1)(x-(-3)
y=-2(x-1)(x+3)