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x1 = -1 - √5 / 2, x2 = -1 - √5 / 2
D = R - {-1 -√5 / 2, -1 +√5 / 2}
(f/g)' = f'g - fg' / g²
(x³ - 2x +1 / x² + x - 1)' = (3x² - 2)(x² + x - 1) - (x³ - 2x +1)(2x + 1) / (x² + x - 1)² =
= 3x^4 +3x³ - 3x² - 2x² - 2x +2 -2x^4 - x³ +4x² + 2x - 2x -1 / (x² + x - 1)² =
= x^4 + 2x³ - x² - 2x +1 / (x² + x - 1)² = (x² + x - 1)² / (x² + x - 1)² = 1 tak można podzielić przy założeniu, że x∈D