Proszę o zrobienie zadań z załącznika.
Jeżeli ktos zrobi mniej niż połowę zgłaszam spam.
bez 2-ch zadan, musze konczyc na dzisiaj
ale miala byc polowa, a jest wiecej :)
11 - b
18 + 24 * 24/18 = 50
12 -d
√3 + 2/√3 = 3/√3 + 2/√3 = 5/√3
13 -c
log(2) 3 - log(2) 5 = log(2) 3/5
log(2) x + log(2) 3/5 = log(2) 5
log(2) (3x/5) = log(2) 5
3x/5 = 5
3x = 25
x = 25/3
14 -
15 -d
a(3) = 6
a(5) = 4
a(5) = a(3) + 2r
r = -1
a(1) = a(3) - 2r = 8
16 -c
a(n) = [2n + 1]/[3n - 1]
a(n+2) = [2(n+2)+1] / [3(n+2) - 1] = [2n + 4 + 1] / [3n + 6 - 1] = (2n + 5) / (3n + 5)
17 -a
a(n) = n² -9n + 18
a(n) = (n-3)(n-6)
pomiedzy 3 a 6 sa 4 i 5 i dla nich wynik jest ujemny
18 -
19 -b
S = (9n + 7n²) / 2
S(1) =8
S(2) = (18+7*4)/2 = (18+28)/2 = 46/2 = 23
a(1) = 8
S(2) = a(1) + a(1) + r
23 = 8 + 8 + r
r = 7
20 -c
a(1) = -15
r = 2
a(n) = -15 + r * (n-1)
-15 + r * (n-1) < 0
-15 + 2n - 2 < 0
2n < 17
n < 8,5
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
bez 2-ch zadan, musze konczyc na dzisiaj
ale miala byc polowa, a jest wiecej :)
11 - b
18 + 24 * 24/18 = 50
12 -d
√3 + 2/√3 = 3/√3 + 2/√3 = 5/√3
13 -c
log(2) 3 - log(2) 5 = log(2) 3/5
log(2) x + log(2) 3/5 = log(2) 5
log(2) (3x/5) = log(2) 5
3x/5 = 5
3x = 25
x = 25/3
14 -
15 -d
a(3) = 6
a(5) = 4
a(5) = a(3) + 2r
r = -1
a(1) = a(3) - 2r = 8
16 -c
a(n) = [2n + 1]/[3n - 1]
a(n+2) = [2(n+2)+1] / [3(n+2) - 1] = [2n + 4 + 1] / [3n + 6 - 1] = (2n + 5) / (3n + 5)
17 -a
a(n) = n² -9n + 18
a(n) = (n-3)(n-6)
pomiedzy 3 a 6 sa 4 i 5 i dla nich wynik jest ujemny
18 -
19 -b
S = (9n + 7n²) / 2
S(1) =8
S(2) = (18+7*4)/2 = (18+28)/2 = 46/2 = 23
a(1) = 8
S(2) = a(1) + a(1) + r
23 = 8 + 8 + r
r = 7
20 -c
a(1) = -15
r = 2
a(n) = -15 + r * (n-1)
-15 + r * (n-1) < 0
-15 + 2n - 2 < 0
2n < 17
n < 8,5