Question

Proszę o zrobienie tych zadań.

Answer 1

zad1a 

(3⁻²)⁺³÷3⁸= 3⁺²

b/  (√2+2)²= 2+4√2+4= 4√2+6

c/  √9×16+9×4+9×5= √144+36+45= √225=15

d/  (a²)⁷÷a⁴÷a⁶= a⁴

e/   2∧½×8∧½+ 12∧½×3∧½= √2×√8 + √12×√3= √16+√36=4+6=10

zad2

     2+√5 / √5-1 = (2+√5)×(√5+1) / (√5-1)(√5+1) = 2√5+2+5+√5 / 5-1 =

     3√5+7 / 4

zad3a

     (2-x)(2+x)+(x+3)²=x-7

4-x²+x²+6x+9=x-7

6x-x= -4-9-7

5x= -20

x= -4

zad3b

   (x-3)(x+2)+(5-x)(x+1)=0

x²+2x-3x-6+5x+5-x²-x=0

2x-3x+5x-x=6-5

3x=1 /:3

x=  ¹/₃  

 

zad4

2(x-1)²-(x+3)² ≤ x(x-2)+1

2(x²-2x+1)-x²-6x-9 ≤ x²-2x+1

2x²-4x+2-x²-6x-9 ≤x²-2x+1

-8x≤14

x≥ -14/8

x≥ -1¾

 

 

 

zad5

a)  (4+3y)(4-3y)-(4-y)²=16-9y²-16+8y-y²= -10y²+8y = -2y(5y-4)

b)  (2x+y)(x-3y)-x² = 2x²-6xy+xy-3y²-x²= x²-3y²-5xy