Question

Proszę o zrobienie tych zadań.

Answer 1

zad1a/

(4⁻⁵)⁻²÷4⁹=4¹=4

b/   (1-√3)²= 1-2√3+3= -2√3+4= -2(√3-2)

c/    √25×9 + 14×25 + 2×25= √225+350+50=√625=25

d/    (a³)⁴× a² ÷ a⁶÷a²= a¹²⁺²⁻⁶⁻² = a⁶

e/    3∧½ × 3∧½ + 32∧½ × 2∧½= √3×√3 + √32×√2= 3+ √64= 3+8=11

 

zad2

3-√2 / √2+2 = (3-√2)(√2-2) / (√2+2)(√2-2)= (3√2-6-2+2√2) / (2-4) = 5√2-8 / (-2)= -5√2÷2 +4

 

zad3a

(x+3)²-(4-x)(4+x) = 2(x-1)²+1

x²+6x+9-16+x²= 2(x²-2x+1)+1

2x²+6x-7=2x²-4x+2+1

10x= 3+7

x= 10/10

x= 1

 

b/

4x-(x-5)(x-7)= x(1-x)

4x-(x²-7x-5x+35)= x-x²

4x-x²+12x-35= x-x²

15x=35

x=35/15

x= 2⅓

 

zad4

2(x-5)² - 3(x+2)² < 6-x²

2(x²-10x+25) - 3(x²+4x+4) <6-x²

2x²-20x+50-3x²-12x-12 < 6-x²

2x²-3x²+x²-32x <6-38

-32x < -32

x>32/32

x>1

 

zad5a

7(x²-2) - 4(x+3)(x-3)= 7x²-14-4(x²-9) = 7x²-14-4x²+36= 3x²+22

 

5b/

4x-(4x+y)(1-2y)= 4x-(4x-8xy+y-2y²)= 4x-4x+8xy-y+2y²= 2y²-y+8xy