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x-1=0→x=1
3+x=0→x=-3
1)x<-3 to |x-1|=-x+1, bo x-1<0 i |3+x|=-3-x, bo x+3<0
-x+1=-x-3
0=-4 sprzeczne
2)-3≤x≤1 to |x-1|=-x+1, bo x-1<0 i |3+x|=3+x, bo x+3>0
-x+1=3+x
-2x=2
x=-1 spełnia zał.-3≤x≤1
3)x>1 to |x-1|=x-1, bo x-1>0 i |3+x|=3+x, bo x+3>0
x-1=3+x
0=4
sprzeczne
odp. x=-1