/1⅓/³
√2⁷₉=
/3/²÷√9=
6²·/⅔/³=
proszę o obliczenie,bo coś mi się wydaje że nauczyciel mi za te zadania złą ocene wstawił plissss
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(1i 1/3 )³ = (4/3)³ = 64/27 = 2 i 10/27
√2 i 7/9 = √25/9 = 5/3
(3)² : √9 = 9 : 3 = 3
6² * (2/3)³ = 36 * 8/27 = 288/27 =10 i 18/27= 10 i 2/3
(1i1/3) do3 = (4/3)do3 = 64/27 = 2i10/27
Pierw.z 2i7/9 = Pierw.z 25/9 = 5/3 = 1 i2/3
(3) do2 : pierw.z 9 = 9 : 3 = 3
6 do2* (2/3)do3 = 36 * 8/27 = 288/27= 10 i18/27 = 10 i2/3