zad1 zapisz w jak najprostszej postaci a] 3(2x-1)+4(1-x) b 2(7x+5)-6(x-2) c -2x(8-x)-5(x do kwadratu +3x) d 5(3-2x)-(4x+6\·3
dam naj..
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a) 3(2x-1)+4(1-x)=6x-3+4-4x=2x-1
b) 2(7x+5)-6(x-2)=14x+10-6x+12=8x+2
c)-2x(8-x)-5(x^ +3x)=-16x+2x^-5x^-15x^=-16x+2x^-20x^=-16x+-18x^
d) 5(3-2x)-(4x+6\·3=15-10x-12x+18=-22x+33
PS. ^ ---> to znaczy do kwadratu
a) 6x-3+4-4x=2x+1
b) 14x+10-6x+12= 8x+22
c) -16x+2x(kwadrat)-5x(kwadrat)-15x= x-3x(kwaadrat)
d) 15-10x-12x-18= -22x-3