Proszę o obliczenia: Oblicz masę 1800 mmola Mg(OH)2. Pomoc!!!!!!!!!!!!!!
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Proszę o obliczenia: Oblicz masę 1800 mmola Mg(OH)2. Pomoc!!!!!!!!!!!!!!
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z wzoru na n=m/M
n - liczba moli
m - masa
M - masa molowa
n = 1800 mol
M = 58 g/mol
m = ?
1800 = m/58 /*58
m = 104400 [g]