potrzebuje na dzis sin alfa-cos alfa --------------------- sin alfa +cos alfa , jezeli tg alfa = 2 to pierwsze to ulamek jeden duzy pomocy
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sinL-cosL
-----------------=?
sinL+cosL
tgL=2
tgL=sinL/cosL=2/1
sinL=2cosL
sinL-cosL
-----------------=
sinL+cosL
2cosL-cosL
------------------=
2cosL+cosL
cosL/3cosL=1/3
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