Pomóżcie Dany jest ciąg geometryczny 36,18,9,.... Wyznacz: a) a5 b)a7 c)an d)a2k-1
q=18/36=1/2
a
a5=a1*q^4
a5=36*(1/2)^4=36*1/16=9/4
b
a7=a1*q^6
a7=36*(1/2)^6=36*1/64=9/16
c
an=a1*q^(n-1)
an=36*(1/2)^(n-1)
d
a2k-1=a1*q(2k-2)
a2k-1=36*(1/2)^(2k-2)
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q=18/36=1/2
a
a5=a1*q^4
a5=36*(1/2)^4=36*1/16=9/4
b
a7=a1*q^6
a7=36*(1/2)^6=36*1/64=9/16
c
an=a1*q^(n-1)
an=36*(1/2)^(n-1)
d
a2k-1=a1*q(2k-2)
a2k-1=36*(1/2)^(2k-2)
q=18/36=1/2
a
a5=a1*q^4
a5=36*(1/2)^4=36*1/16=9/4
b
a7=a1*q^6
a7=36*(1/2)^6=36*1/64=9/16
c
an=a1*q^(n-1)
an=36*(1/2)^(n-1)
d
a2k-1=a1*q(2k-2)
a2k-1=36*(1/2)^(2k-2)