Pole wycinka kołowego wynosi 30π², łuk tego wycinka ma długość 12π. Oblicz promień.
P= pi r² * α/360
l= 2 pi r * α/360
30 pi = pi r² * α/360
12 pi = 2 pi r * α/360
30 = r² * α/360
6 = r * α/360
6/r = 30/ r²
30r = 6r²
6r(r-5) = 0
r= o sprz ∨ r-5=0
r=5
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P= pi r² * α/360
l= 2 pi r * α/360
30 pi = pi r² * α/360
12 pi = 2 pi r * α/360
30 = r² * α/360
6 = r * α/360
6/r = 30/ r²
30r = 6r²
6r(r-5) = 0
r= o sprz ∨ r-5=0
r=5