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V=1/3Pp * h
Pb=60πcm²
r=6cm
Pb=π * r * l
60π=π * 6 * l /:π
60=6 * l /:6
l=10[cm]
6²+h²=10²
36+h²=100
h²=100-36
h²=64 /√
h=8[cm]
Pp=πr²
Pp=π6²
Pp=36π
V=1/3Pp * h
V=1/3 * 36π * 8
V=12π *8
V=96π[cm³]
Odp. Objętośc tego stożka wynosi 96π cm³