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4πr²=196π/:4π
r²=49
r=√49
r=7
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πR²=49π pole calkowite kola wielkiego kuli
πR²=49π/:π
R²=49
R=√49
R=7
r=R a zatem objetosci tych kul sa jednakowe (maja te same promienie)
49 pi
49p =p r² :p
49=r²
7=r
V=4/3p r³
V=4/3*343
V=457,(3)
457,(3)>196
Objętość II