September 2018 1 6 Report
A) 1-sin²α / 1-cos²α

b) cos²α-1 / sin²α-1

c) 1+cos²α = sin²α

d) 1-cos²α+sin²α

e) (tgα * cosα)2 + (ctgα * sinα)²

f) 1-sin²α - ctg²α * sin²α


* - razy
/ - podzielić

Bardzo proszę o szybką odpowiedź! ;)

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