Podziel wielomian:
(2x^3+4x^2-5x+6):(x^2-x+2)
x^3, x^2 - potęgi.
2x+6
---------------------
(2x³+4x²-5x+6):(x²-x+2)-
-2x³+2x²-4x
-------------------
= 6x²-9x+6
-6x²+6x-12
--------------------
= -3x-6 <-- reszta
liczę na naj
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
2x+6
---------------------
(2x³+4x²-5x+6):(x²-x+2)-
-2x³+2x²-4x
-------------------
= 6x²-9x+6
-6x²+6x-12
--------------------
= -3x-6 <-- reszta
liczę na naj