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C=12u
H=1u
O=16u
12n+1*(2n+1)+16+1=74u
12n+2n+1+16+1=74u
14n+18=74u
14n=74-18
14n=56/14
n=4
C4H9OH- butanol
12n+2n+1+16+1=74
14n+18=74
14n=74-18
14n=56
n=4
Szukanym alkoholem jest C4H9OH (butanol)