Plis bantuin aku ga ngerti soalnya :(
1 )
2) nilai xy pada persamaan![\left[\begin{array}{ccc}2&6\\3&8\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}24\\31\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%266%5C%5C3%268%5C%5C%5Cend%7Barray%7D%5Cright%5D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D+%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D24%5C%5C31%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}2&6\\3&8\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}24\\31\end{array}\right]")
adalah
1 )
2) nilai xy pada persamaan
Abdulhady
![1.)\int\limits^4_0 { \sqrt{2}x+1 } \, dx \\=\left [ \frac{\sqrt{2}}{2}x^2+x|_{0}^{4} \right ]\\=\left [ (\frac{\sqrt{2}}{2}4^2+4) \right ]\\=8\sqrt{2}+4\\=4(2\sqrt{2}+1)\\\\\textup{2. Matriks di atas merupakan bentuk lain dari persamaan linier}\\\\2x+6y=24\rightarrow \times 3\\3x+8y=31\rightarrow \times 2\\\\6x+18y=72\\6x+16y=62\\--------^-\\2y=10\\y=5\\\\\textup{Subtitusikan nilai y=5 ke dalam salah satu persamaan}\\2x+6(5)=24\\2x=24-30=-6\\x=-3\\\\\boxed{x=-3 \,\textup{ dan }y=5}](https://tex.z-dn.net/?f=+1.%29%5Cint%5Climits%5E4_0+%7B+%5Csqrt%7B2%7Dx%2B1+%7D+%5C%2C+dx+%5C%5C%3D%5Cleft+%5B+%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7Dx%5E2%2Bx%7C_%7B0%7D%5E%7B4%7D+%5Cright+%5D%5C%5C%3D%5Cleft+%5B+%28%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D4%5E2%2B4%29+%5Cright+%5D%5C%5C%3D8%5Csqrt%7B2%7D%2B4%5C%5C%3D4%282%5Csqrt%7B2%7D%2B1%29%5C%5C%5C%5C%5Ctextup%7B2.+Matriks+di+atas+merupakan+bentuk+lain+dari+persamaan+linier%7D%5C%5C%5C%5C2x%2B6y%3D24%5Crightarrow+%5Ctimes+3%5C%5C3x%2B8y%3D31%5Crightarrow+%5Ctimes+2%5C%5C%5C%5C6x%2B18y%3D72%5C%5C6x%2B16y%3D62%5C%5C--------%5E-%5C%5C2y%3D10%5C%5Cy%3D5%5C%5C%5C%5C%5Ctextup%7BSubtitusikan+nilai+y%3D5+ke+dalam+salah+satu+persamaan%7D%5C%5C2x%2B6%285%29%3D24%5C%5C2x%3D24-30%3D-6%5C%5Cx%3D-3%5C%5C%5C%5C%5Cboxed%7Bx%3D-3+%5C%2C%5Ctextup%7B+dan+%7Dy%3D5%7D "1.)\int\limits^4_0 { \sqrt{2}x+1 } \, dx \\=\left [ \frac{\sqrt{2}}{2}x^2+x|_{0}^{4} \right ]\\=\left [ (\frac{\sqrt{2}}{2}4^2+4) \right ]\\=8\sqrt{2}+4\\=4(2\sqrt{2}+1)\\\\\textup{2. Matriks di atas merupakan bentuk lain dari persamaan linier}\\\\2x+6y=24\rightarrow \times 3\\3x+8y=31\rightarrow \times 2\\\\6x+18y=72\\6x+16y=62\\--------^-\\2y=10\\y=5\\\\\textup{Subtitusikan nilai y=5 ke dalam salah satu persamaan}\\2x+6(5)=24\\2x=24-30=-6\\x=-3\\\\\boxed{x=-3 \,\textup{ dan }y=5}")
0 votes
Thanks 0
izharulhaq78
no. 2 yang ditanya xy
rizkyaulina
no ga ada di option
izharulhaq78
![\displaystyle \left[\begin{array}{ccc}2&6\\3&8\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}24\\31\end{array}\right]\\\\\left[\begin{array}{ccc}2x+6y\\3x+8y\end{array}\right]=\left[\begin{array}{ccc}24\\31\end{array}\right]\\\\2x+6y=24\\2(x+3y)=24\\x+3y=12\\x=12-3y\\\\3x+8y=31\\3(12-3y)+8y=31\\36-9y+8y=31\\-y=31-36\\-y=-5\\y=5\\\\xy=(12-3y)(y)\\xy=(12-3(5))(5)\\xy=(12-15)(5)\\xy=(-3)(5)\\\boxed{\boxed{xy=-15}}](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%266%5C%5C3%268%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D24%5C%5C31%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2x%2B6y%5C%5C3x%2B8y%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D24%5C%5C31%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C2x%2B6y%3D24%5C%5C2%28x%2B3y%29%3D24%5C%5Cx%2B3y%3D12%5C%5Cx%3D12-3y%5C%5C%5C%5C3x%2B8y%3D31%5C%5C3%2812-3y%29%2B8y%3D31%5C%5C36-9y%2B8y%3D31%5C%5C-y%3D31-36%5C%5C-y%3D-5%5C%5Cy%3D5%5C%5C%5C%5Cxy%3D%2812-3y%29%28y%29%5C%5Cxy%3D%2812-3%285%29%29%285%29%5C%5Cxy%3D%2812-15%29%285%29%5C%5Cxy%3D%28-3%29%285%29%5C%5C%5Cboxed%7B%5Cboxed%7Bxy%3D-15%7D%7D "\displaystyle \left[\begin{array}{ccc}2&6\\3&8\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}24\\31\end{array}\right]\\\\\left[\begin{array}{ccc}2x+6y\\3x+8y\end{array}\right]=\left[\begin{array}{ccc}24\\31\end{array}\right]\\\\2x+6y=24\\2(x+3y)=24\\x+3y=12\\x=12-3y\\\\3x+8y=31\\3(12-3y)+8y=31\\36-9y+8y=31\\-y=31-36\\-y=-5\\y=5\\\\xy=(12-3y)(y)\\xy=(12-3(5))(5)\\xy=(12-15)(5)\\xy=(-3)(5)\\\boxed{\boxed{xy=-15}}")
1 votes
Thanks 2
rizkyaulina
no 1 ga ada di option
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