" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
b² - 4ac = 0
(-2(p+3))² - 4(p+1)(3p) = 0
4(p² + 6p + 9) - 4(3p² + 3p) = 0
4p² + 24p + 36 - 12p² - 12p = 0
-8p² + 12p + 36 = 0
-4 (p - 3)(2p + 3) = 0
p = 3
p = -3/2
(p + 1)x² - 2(p + 3)x + 3p = 0
a = p + 1
b = -2(p + 3)
c = 3p
Syarat akar kembar adalah D = 0.
D = b² - 4ac
0 = (-2(p + 3))² - (4(p + 1)(3p))
0 = (-2p - 6)² - (3p(4p + 4))
0 = 4p² + 24p + 36 - (12p² + 12p)
0 = 4p² + 24p + 36 - 12p² - 12p
0 = -8p² + 12p + 36
0 = -8p² - 12p + 24p + 36
0 = -4p(2p + 3) + 12(2p + 3)
0 = (-4p + 12) (2p + 3)
0 = -4p + 12
4p = 12
p = 3
0 = 2p + 3
-2p = 3
p = -3/2
Jadi nilai p adalah 3 atau -3/2.