Wiadomo, że [email protected]=1/pierwiastek z 2. Oblicz [email protected], [email protected], [email protected]
W razie czego @ to alfa :p
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b=1
c=√2
a=√[(√2)²-1²]=√[2-1]=√1=1
czyli to trójkąt równoramienny
sinα=1/√2=√2/2
tgα=1/1=1
ctgα=1/1=1