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114,818u=(100%-x) * 113u + x *115u. /100% |*100
11481,8 = 11300 - 113x +115x
2x = 11300 - 11481,8
2x= 181,8 |:2
x= 90,9 %
100% - 90,9% = 9,1%
Zawartość procentowa izotopu 113 to 9,1% a 115 90,9%.
Pozdrawiam..:)